If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2+5x+10=8
We move all terms to the left:
3x^2+5x+10-(8)=0
We add all the numbers together, and all the variables
3x^2+5x+2=0
a = 3; b = 5; c = +2;
Δ = b2-4ac
Δ = 52-4·3·2
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-1}{2*3}=\frac{-6}{6} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+1}{2*3}=\frac{-4}{6} =-2/3 $
| 50+2.50x=60+2x | | 4j+8=56 | | 38+3x=5(1-6x) | | -2-2x=x-x | | −809=5(6+12p)+1 | | 38+3x=5(1-6x | | 5-6x+2x=-39 | | -3+a=14 | | 15b–62=9b-26 | | 3=(-1/2)x | | 1/2(g+25)=50 | | 3(x−4)−2x=6x+13 | | 3x+2=-26 | | f−29=12 | | 107/12=-6x+7x+8 | | 2^×+3=4y | | -7(-2p-2)=14p+14 | | 9b–26=15b–62 | | 7^(4x+1)=128 | | n−6(−5n−3)=18+7n | | -8(2m-6)=8m+24 | | 2m-3=43 | | 7x+(5-3x)=5 | | 6x+4=28* | | 54=3(2x-4) | | 205=7d-3(-6d+15) | | 3(h-10)+-1=-19 | | -7+b=-8(7b+8) | | 9v+6+6v=-14+20v | | 180=30+x+2x | | 5(6)-3y=-3 | | 13-13x=-13(x-1) |